Base | Representation |
---|---|
bin | 110001011000010101… |
… | …000001001101011111 |
3 | 12001212011022220121211 |
4 | 301120111001031133 |
5 | 1332042001400133 |
6 | 40205135005251 |
7 | 3554631264136 |
oct | 613025011537 |
9 | 161764286554 |
10 | 53021512543 |
11 | 2053929715a |
12 | a338969827 |
13 | 4ccca46c7c |
14 | 27cdb3691d |
15 | 15a4c87bcd |
hex | c5854135f |
53021512543 has 4 divisors (see below), whose sum is σ = 54314720208. Its totient is φ = 51728304880.
The previous prime is 53021512513. The next prime is 53021512567. The reversal of 53021512543 is 34521512035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53021512543 - 221 = 53019415391 is a prime.
It is a super-3 number, since 3×530215125433 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53021512513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 646603771 + ... + 646603852.
It is an arithmetic number, because the mean of its divisors is an integer number (13578680052).
Almost surely, 253021512543 is an apocalyptic number.
53021512543 is a deficient number, since it is larger than the sum of its proper divisors (1293207665).
53021512543 is a wasteful number, since it uses less digits than its factorization.
53021512543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1293207664.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 53021512543 in words is "fifty-three billion, twenty-one million, five hundred twelve thousand, five hundred forty-three".
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