Base | Representation |
---|---|
bin | 110001011000011000… |
… | …011111010000010011 |
3 | 12001212020001010012201 |
4 | 301120120133100103 |
5 | 1332042220001120 |
6 | 40205210304031 |
7 | 3554642102542 |
oct | 613030372023 |
9 | 161766033181 |
10 | 53022422035 |
11 | 20539858500 |
12 | a339128017 |
13 | 4cccca4c2b |
14 | 27cdcd2159 |
15 | 15a4db740a |
hex | c5861f413 |
53022422035 has 12 divisors (see below), whose sum is σ = 69937013664. Its totient is φ = 38561761040.
The previous prime is 53022422027. The next prime is 53022422081.
It is a happy number.
53022422035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53022422035 - 23 = 53022422027 is a prime.
It is a super-2 number, since 2×530224220352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53022421994 and 53022422012.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 43819579 + ... + 43820788.
It is an arithmetic number, because the mean of its divisors is an integer number (5828084472).
Almost surely, 253022422035 is an apocalyptic number.
53022422035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53022422035 is a deficient number, since it is larger than the sum of its proper divisors (16914591629).
53022422035 is a wasteful number, since it uses less digits than its factorization.
53022422035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87640394 (or 87640383 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 28.
The spelling of 53022422035 in words is "fifty-three billion, twenty-two million, four hundred twenty-two thousand, thirty-five".
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