53023000155535 has 4 divisors (see below), whose sum is σ = 63627600186648. Its totient is φ = 42418400124424.

The previous prime is 53023000155523. The next prime is 53023000155599. The reversal of 53023000155535 is 53555100032035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53023000155535 - 2¹⁵ = 53023000122767 is a prime.

It is a super-2 number, since 2×53023000155535² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53023000155494 and 53023000155503.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5302300015549 + ... + 5302300015558.

It is an arithmetic number, because the mean of its divisors is an integer number (15906900046662).

Almost surely, 2^{53023000155535} is an apocalyptic number.

53023000155535 is a deficient number, since it is larger than the sum of its proper divisors (10604600031113).

53023000155535 is a wasteful number, since it uses less digits than its factorization.

53023000155535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10604600031112.

The product of its (nonzero) digits is 168750, while the sum is 37.

The spelling of 53023000155535 in words is "fifty-three trillion, twenty-three billion, one hundred fifty-five thousand, five hundred thirty-five".