Search a number
-
+
53023050053 = 55117962009
BaseRepresentation
bin110001011000011010…
…111000100101000101
312001212021020000200122
4301120122320211011
51332042400100203
640205231551325
73554650326521
oct613032704505
9161767200618
1053023050053
112053a147326
12a33938b545
135000164a3c
1427d0016d81
1515a4e8d538
hexc586b8945

53023050053 has 4 divisors (see below), whose sum is σ = 53024067180. Its totient is φ = 53022032928.

The previous prime is 53023050019. The next prime is 53023050079. The reversal of 53023050053 is 35005032035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 28612737409 + 24410312644 = 169153^2 + 156238^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53023050053 is a prime.

It is a super-2 number, since 2×530230500532 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53023070053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425888 + ... + 536121.

It is an arithmetic number, because the mean of its divisors is an integer number (13256016795).

Almost surely, 253023050053 is an apocalyptic number.

It is an amenable number.

53023050053 is a deficient number, since it is larger than the sum of its proper divisors (1017127).

53023050053 is an equidigital number, since it uses as much as digits as its factorization.

53023050053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017126.

The product of its (nonzero) digits is 6750, while the sum is 26.

Adding to 53023050053 its reverse (35005032035), we get a palindrome (88028082088).

The spelling of 53023050053 in words is "fifty-three billion, twenty-three million, fifty thousand, fifty-three".

Divisors: 1 55117 962009 53023050053