Base | Representation |
---|---|
bin | 110001011000011100… |
… | …010101111010011111 |
3 | 12001212021221110002211 |
4 | 301120130111322133 |
5 | 1332042444313401 |
6 | 40205244101251 |
7 | 3554653511221 |
oct | 613034257237 |
9 | 161767843084 |
10 | 53023432351 |
11 | 2053a38857a |
12 | a339534827 |
13 | 5000269a56 |
14 | 27d00b6411 |
15 | 15a5016951 |
hex | c58715e9f |
53023432351 has 8 divisors (see below), whose sum is σ = 54990004320. Its totient is φ = 51066072288.
The previous prime is 53023432339. The next prime is 53023432459. The reversal of 53023432351 is 15323432035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53023432351 - 27 = 53023432223 is a prime.
It is a super-2 number, since 2×530234323512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53023432321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2291251 + ... + 2314276.
It is an arithmetic number, because the mean of its divisors is an integer number (6873750540).
Almost surely, 253023432351 is an apocalyptic number.
53023432351 is a deficient number, since it is larger than the sum of its proper divisors (1966571969).
53023432351 is a wasteful number, since it uses less digits than its factorization.
53023432351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4605953.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 53023432351 its reverse (15323432035), we get a palindrome (68346864386).
The spelling of 53023432351 in words is "fifty-three billion, twenty-three million, four hundred thirty-two thousand, three hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •