Base | Representation |
---|---|
bin | 111100010010000000111001… |
… | …0100111000111110010111111 |
3 | 2120112102120202020000222000020 |
4 | 1320210001302213013302333 |
5 | 1023444433344232300101 |
6 | 5115421312215303223 |
7 | 216454451220241332 |
oct | 17044016247076277 |
9 | 2515376666028006 |
10 | 530241405353151 |
11 | 143a51131a58748 |
12 | 4b57840597ab13 |
13 | 199b371c3a886b |
14 | 94d1b6c99c619 |
15 | 4147be0bd4136 |
hex | 1e240729c7cbf |
530241405353151 has 4 divisors (see below), whose sum is σ = 706988540470872. Its totient is φ = 353494270235432.
The previous prime is 530241405353111. The next prime is 530241405353237. The reversal of 530241405353151 is 151353504142035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 530241405353151 - 211 = 530241405351103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530241405353111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88373567558856 + ... + 88373567558861.
It is an arithmetic number, because the mean of its divisors is an integer number (176747135117718).
Almost surely, 2530241405353151 is an apocalyptic number.
530241405353151 is a deficient number, since it is larger than the sum of its proper divisors (176747135117721).
530241405353151 is a wasteful number, since it uses less digits than its factorization.
530241405353151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176747135117720.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 530241405353151 its reverse (151353504142035), we get a palindrome (681594909495186).
The spelling of 530241405353151 in words is "five hundred thirty trillion, two hundred forty-one billion, four hundred five million, three hundred fifty-three thousand, one hundred fifty-one".
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