Base | Representation |
---|---|
bin | 111100010010000001101001… |
… | …0011001101001000101111111 |
3 | 2120112102201220020001001002112 |
4 | 1320210003102121221011333 |
5 | 1024000000142140313010 |
6 | 5115422135504444235 |
7 | 216454536103214213 |
oct | 17044032231510577 |
9 | 2515381806031075 |
10 | 530243012432255 |
11 | 143a51887124aa1 |
12 | 4b57879401967b |
13 | 199b391731c845 |
14 | 94d1c821b6943 |
15 | 4147c86d30a05 |
hex | 1e240d266917f |
530243012432255 has 16 divisors (see below), whose sum is σ = 636397941183840. Its totient is φ = 424123531214208.
The previous prime is 530243012432201. The next prime is 530243012432291. The reversal of 530243012432255 is 552234210342035.
It is a cyclic number.
It is not a de Polignac number, because 530243012432255 - 222 = 530243008237951 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 810703901 + ... + 811357689.
It is an arithmetic number, because the mean of its divisors is an integer number (39774871323990).
Almost surely, 2530243012432255 is an apocalyptic number.
530243012432255 is a deficient number, since it is larger than the sum of its proper divisors (106154928751585).
530243012432255 is a wasteful number, since it uses less digits than its factorization.
530243012432255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680650.
The product of its (nonzero) digits is 864000, while the sum is 41.
The spelling of 530243012432255 in words is "five hundred thirty trillion, two hundred forty-three billion, twelve million, four hundred thirty-two thousand, two hundred fifty-five".
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