Base | Representation |
---|---|
bin | 110001011000011111… |
… | …101010000101011011 |
3 | 12001212100120121012221 |
4 | 301120133222011123 |
5 | 1332043210121103 |
6 | 40205314444511 |
7 | 3554664061003 |
oct | 613037520533 |
9 | 161770517187 |
10 | 53024301403 |
11 | 2053a9214a7 |
12 | a339893737 |
13 | 50004b2498 |
14 | 27d0261003 |
15 | 15a51391bd |
hex | c587ea15b |
53024301403 has 8 divisors (see below), whose sum is σ = 53155487840. Its totient is φ = 52893207360.
The previous prime is 53024301373. The next prime is 53024301413. The reversal of 53024301403 is 30410342035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53024301403 - 25 = 53024301371 is a prime.
It is a super-3 number, since 3×530243014033 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53024301413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1206133 + ... + 1249321.
It is an arithmetic number, because the mean of its divisors is an integer number (6644435980).
Almost surely, 253024301403 is an apocalyptic number.
53024301403 is a deficient number, since it is larger than the sum of its proper divisors (131186437).
53024301403 is a wasteful number, since it uses less digits than its factorization.
53024301403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46197.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 53024301403 its reverse (30410342035), we get a palindrome (83434643438).
The spelling of 53024301403 in words is "fifty-three billion, twenty-four million, three hundred one thousand, four hundred three".
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