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53025044441 = 107495561163
BaseRepresentation
bin110001011000100010…
…011111011111011001
312001212101222100110212
4301120202133133121
51332043402410231
640205342420505
73555003304205
oct613042373731
9161771870425
1053025044441
1120540289786
12a339b91735
1350006b2755
1427d03b5b05
1515a523442b
hexc5889f7d9

53025044441 has 4 divisors (see below), whose sum is σ = 53520605712. Its totient is φ = 52529483172.

The previous prime is 53025044419. The next prime is 53025044473. The reversal of 53025044441 is 14444052035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53025044441 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 53025044398 and 53025044407.

It is not an unprimeable number, because it can be changed into a prime (53025041441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 247780475 + ... + 247780688.

It is an arithmetic number, because the mean of its divisors is an integer number (13380151428).

Almost surely, 253025044441 is an apocalyptic number.

It is an amenable number.

53025044441 is a deficient number, since it is larger than the sum of its proper divisors (495561271).

53025044441 is a wasteful number, since it uses less digits than its factorization.

53025044441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 495561270.

The product of its (nonzero) digits is 38400, while the sum is 32.

Adding to 53025044441 its reverse (14444052035), we get a palindrome (67469096476).

The spelling of 53025044441 in words is "fifty-three billion, twenty-five million, forty-four thousand, four hundred forty-one".

Divisors: 1 107 495561163 53025044441