Base | Representation |
---|---|
bin | 1111011011101010110… |
… | …11100011010100011011 |
3 | 1212200200010001120000121 |
4 | 13231311123203110123 |
5 | 32141423242243420 |
6 | 1043332150014111 |
7 | 53211055163104 |
oct | 7556533432433 |
9 | 1780603046017 |
10 | 530251134235 |
11 | 194972a3a389 |
12 | 86924047337 |
13 | 3b0055618c4 |
14 | 1b942b613ab |
15 | dbd68172aa |
hex | 7b756e351b |
530251134235 has 4 divisors (see below), whose sum is σ = 636301361088. Its totient is φ = 424200907384.
The previous prime is 530251134233. The next prime is 530251134241. The reversal of 530251134235 is 532431152035.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 532431152035 = 5 ⋅106486230407.
It is a cyclic number.
It is not a de Polignac number, because 530251134235 - 21 = 530251134233 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 530251134235.
It is not an unprimeable number, because it can be changed into a prime (530251134233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53025113419 + ... + 53025113428.
It is an arithmetic number, because the mean of its divisors is an integer number (159075340272).
Almost surely, 2530251134235 is an apocalyptic number.
530251134235 is a deficient number, since it is larger than the sum of its proper divisors (106050226853).
530251134235 is a wasteful number, since it uses less digits than its factorization.
530251134235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106050226852.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 530251134235 in words is "five hundred thirty billion, two hundred fifty-one million, one hundred thirty-four thousand, two hundred thirty-five".
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