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530253345305 = 5106050669061
BaseRepresentation
bin1111011011101011000…
…11111111001000011001
31212200200021012220001002
413231311203333020121
532141424324022210
61043332305234345
753211113032265
oct7556543771031
91780607186032
10530253345305
1119497420a612
12869249329b5
133b005b57128
141b9431790a5
15dbd6b024a5
hex7b758ff219

530253345305 has 4 divisors (see below), whose sum is σ = 636304014372. Its totient is φ = 424202676240.

The previous prime is 530253345283. The next prime is 530253345311. The reversal of 530253345305 is 503543352035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 503543352035 = 5100708670407.

It can be written as a sum of positive squares in 2 ways, for example, as 298872142864 + 231381202441 = 546692^2 + 481021^2 .

It is not a de Polignac number, because 530253345305 - 216 = 530253279769 is a prime.

It is a super-3 number, since 3×5302533453053 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53025334526 + ... + 53025334535.

It is an arithmetic number, because the mean of its divisors is an integer number (159076003593).

Almost surely, 2530253345305 is an apocalyptic number.

It is an amenable number.

530253345305 is a deficient number, since it is larger than the sum of its proper divisors (106050669067).

530253345305 is a wasteful number, since it uses less digits than its factorization.

530253345305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106050669066.

The product of its (nonzero) digits is 405000, while the sum is 38.

The spelling of 530253345305 in words is "five hundred thirty billion, two hundred fifty-three million, three hundred forty-five thousand, three hundred five".

Divisors: 1 5 106050669061 530253345305