Base | Representation |
---|---|
bin | 100110100101001011110… |
… | …1101110011101100111011 |
3 | 200202220202210010001200110 |
4 | 1031022113231303230323 |
5 | 1143334042430324011 |
6 | 15135541223435403 |
7 | 1055044521632511 |
oct | 115122755635473 |
9 | 20686683101613 |
10 | 5302535011131 |
11 | 1764879860186 |
12 | 7178002b5b63 |
13 | 2c6047160157 |
14 | 1449034504b1 |
15 | 92de7724ba6 |
hex | 4d297b73b3b |
5302535011131 has 8 divisors (see below), whose sum is σ = 7070171690560. Its totient is φ = 3534960836232.
The previous prime is 5302535011129. The next prime is 5302535011153. The reversal of 5302535011131 is 1311105352035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5302535011131 - 21 = 5302535011129 is a prime.
It is a super-2 number, since 2×53025350111312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302535011031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15427825 + ... + 15767778.
It is an arithmetic number, because the mean of its divisors is an integer number (883771461320).
Almost surely, 25302535011131 is an apocalyptic number.
5302535011131 is a deficient number, since it is larger than the sum of its proper divisors (1767636679429).
5302535011131 is a wasteful number, since it uses less digits than its factorization.
5302535011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31252265.
The product of its (nonzero) digits is 6750, while the sum is 30.
The spelling of 5302535011131 in words is "five trillion, three hundred two billion, five hundred thirty-five million, eleven thousand, one hundred thirty-one".
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