Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111100100011110001 |
3 | 200202220210011112120220212 |
4 | 1031022120002330203301 |
5 | 1143334100340134213 |
6 | 15135541542313505 |
7 | 1055044620012065 |
oct | 115123002744361 |
9 | 20686704476825 |
10 | 5302540552433 |
11 | 17648819a5473 |
12 | 717802128895 |
13 | 2c6048350427 |
14 | 144904093aa5 |
15 | 92de7e6b9a8 |
hex | 4d2980bc8f1 |
5302540552433 has 8 divisors (see below), whose sum is σ = 5583528635520. Its totient is φ = 5021743169520.
The previous prime is 5302540552429. The next prime is 5302540552447. The reversal of 5302540552433 is 3342550452035.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5302540552433 - 22 = 5302540552429 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302540752433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47617958 + ... + 47729183.
It is an arithmetic number, because the mean of its divisors is an integer number (697941079440).
Almost surely, 25302540552433 is an apocalyptic number.
It is an amenable number.
5302540552433 is a deficient number, since it is larger than the sum of its proper divisors (280988083087).
5302540552433 is a wasteful number, since it uses less digits than its factorization.
5302540552433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95350087.
The product of its (nonzero) digits is 1080000, while the sum is 41.
The spelling of 5302540552433 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-two thousand, four hundred thirty-three".
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