Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …1001110100011011000001 |
3 | 200202220210021221010100202 |
4 | 1031022120021310123001 |
5 | 1143334101320312423 |
6 | 15135542045054545 |
7 | 1055044641224564 |
oct | 115123011643301 |
9 | 20686707833322 |
10 | 5302542354113 |
11 | 1764882a16064 |
12 | 717802857455 |
13 | 2c6048831504 |
14 | 1449044024db |
15 | 92de81c5728 |
hex | 4d2982746c1 |
5302542354113 has 4 divisors (see below), whose sum is σ = 5325901571760. Its totient is φ = 5279183136468.
The previous prime is 5302542354107. The next prime is 5302542354139. The reversal of 5302542354113 is 3114532452035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5302542354113 - 26 = 5302542354049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5302502354113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11679608483 + ... + 11679608936.
It is an arithmetic number, because the mean of its divisors is an integer number (1331475392940).
Almost surely, 25302542354113 is an apocalyptic number.
It is an amenable number.
5302542354113 is a deficient number, since it is larger than the sum of its proper divisors (23359217647).
5302542354113 is a wasteful number, since it uses less digits than its factorization.
5302542354113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23359217646.
The product of its (nonzero) digits is 216000, while the sum is 38.
The spelling of 5302542354113 in words is "five trillion, three hundred two billion, five hundred forty-two million, three hundred fifty-four thousand, one hundred thirteen".
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