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5302542354141 = 31767514118047
BaseRepresentation
bin100110100101001100000…
…1001110100011011011101
3200202220210021221010101210
41031022120021310123131
51143334101320313031
615135542045055033
71055044641224634
oct115123011643335
920686707833353
105302542354141
111764882a1608a
12717802857479
132c6048831526
1414490440251b
1592de81c5746
hex4d2982746dd

5302542354141 has 4 divisors (see below), whose sum is σ = 7070056472192. Its totient is φ = 3535028236092.

The previous prime is 5302542354139. The next prime is 5302542354169. The reversal of 5302542354141 is 1414532452035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5302542354141 - 21 = 5302542354139 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5302542354141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5302542354101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 883757059021 + ... + 883757059026.

It is an arithmetic number, because the mean of its divisors is an integer number (1767514118048).

Almost surely, 25302542354141 is an apocalyptic number.

It is an amenable number.

5302542354141 is a deficient number, since it is larger than the sum of its proper divisors (1767514118051).

5302542354141 is a wasteful number, since it uses less digits than its factorization.

5302542354141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1767514118050.

The product of its (nonzero) digits is 288000, while the sum is 39.

The spelling of 5302542354141 in words is "five trillion, three hundred two billion, five hundred forty-two million, three hundred fifty-four thousand, one hundred forty-one".

Divisors: 1 3 1767514118047 5302542354141