Base | Representation |
---|---|
bin | 1111011011101011010… |
… | …10010101100110010001 |
3 | 1212200200101100110211121 |
4 | 13231311222111212101 |
5 | 32141430240311233 |
6 | 1043332405042241 |
7 | 53211133135216 |
oct | 7556552254621 |
9 | 1780611313747 |
10 | 530255010193 |
11 | 194975147457 |
12 | 869253b6381 |
13 | 3b0062bab7c |
14 | 1b94348db0d |
15 | dbd6d3092d |
hex | 7b75a95991 |
530255010193 has 4 divisors (see below), whose sum is σ = 530353447920. Its totient is φ = 530156572468.
The previous prime is 530255010169. The next prime is 530255010211. The reversal of 530255010193 is 391010552035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 391010552035 = 5 ⋅78202110407.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530255010193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (530255010293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49210783 + ... + 49221556.
It is an arithmetic number, because the mean of its divisors is an integer number (132588361980).
Almost surely, 2530255010193 is an apocalyptic number.
It is an amenable number.
530255010193 is a deficient number, since it is larger than the sum of its proper divisors (98437727).
530255010193 is an equidigital number, since it uses as much as digits as its factorization.
530255010193 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98437726.
The product of its (nonzero) digits is 20250, while the sum is 34.
The spelling of 530255010193 in words is "five hundred thirty billion, two hundred fifty-five million, ten thousand, one hundred ninety-three".
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