Base | Representation |
---|---|
bin | 1111011011101011010… |
… | …10011011001010101000 |
3 | 1212200200101101122010022 |
4 | 13231311222123022220 |
5 | 32141430242024000 |
6 | 1043332405340012 |
7 | 53211133261550 |
oct | 7556552331250 |
9 | 1780611348108 |
10 | 530255033000 |
11 | 194975162600 |
12 | 86925407608 |
13 | 3b0062c8374 |
14 | 1b943498160 |
15 | dbd6d37585 |
hex | 7b75a9b2a8 |
530255033000 has 384 divisors, whose sum is σ = 1562633130240. Its totient is φ = 164856384000.
The previous prime is 530255032963. The next prime is 530255033017. The reversal of 530255033000 is 330552035.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 641178587 + ... + 641179413.
It is an arithmetic number, because the mean of its divisors is an integer number (4069357110).
Almost surely, 2530255033000 is an apocalyptic number.
530255033000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 530255033000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (781316565120).
530255033000 is an abundant number, since it is smaller than the sum of its proper divisors (1032378097240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530255033000 is a wasteful number, since it uses less digits than its factorization.
530255033000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1634 (or 1609 counting only the distinct ones).
The product of its (nonzero) digits is 6750, while the sum is 26.
Adding to 530255033000 its reverse (330552035), we get a palindrome (530585585035).
The spelling of 530255033000 in words is "five hundred thirty billion, two hundred fifty-five million, thirty-three thousand".
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