Base | Representation |
---|---|
bin | 111100010010011101010110… |
… | …0111111010111111100110010 |
3 | 2120112122102111000100200222111 |
4 | 1320210322230333113330302 |
5 | 1024001434022132101232 |
6 | 5115505340100555534 |
7 | 216462043444055026 |
oct | 17044725477277462 |
9 | 2515572430320874 |
10 | 530302514331442 |
11 | 143a75040422596 |
12 | 4b58821b0b2baa |
13 | 199b940a80b208 |
14 | 94d4ac884a386 |
15 | 41495ba993047 |
hex | 1e24eacfd7f32 |
530302514331442 has 16 divisors (see below), whose sum is σ = 795517038650880. Its totient is φ = 265130168675328.
The previous prime is 530302514331433. The next prime is 530302514331451. The reversal of 530302514331442 is 244133415203035.
It is an interprime number because it is at equal distance from previous prime (530302514331433) and next prime (530302514331451).
It is a junction number, because it is equal to n+sod(n) for n = 530302514331395 and 530302514331404.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3388717723 + ... + 3388874209.
It is an arithmetic number, because the mean of its divisors is an integer number (49719814915680).
Almost surely, 2530302514331442 is an apocalyptic number.
530302514331442 is a deficient number, since it is larger than the sum of its proper divisors (265214524319438).
530302514331442 is a wasteful number, since it uses less digits than its factorization.
530302514331442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 280425.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 530302514331442 its reverse (244133415203035), we get a palindrome (774435929534477).
The spelling of 530302514331442 in words is "five hundred thirty trillion, three hundred two billion, five hundred fourteen million, three hundred thirty-one thousand, four hundred forty-two".
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