Base | Representation |
---|---|
bin | 100110100101011011001… |
… | …1100011100011011011101 |
3 | 200202222002201012022020201 |
4 | 1031022312130130123131 |
5 | 1143341121420144203 |
6 | 15140104321343501 |
7 | 1055063351650261 |
oct | 115126634343335 |
9 | 20688081168221 |
10 | 5303050553053 |
11 | 1765013872490 |
12 | 717924a97b91 |
13 | 2c60c9bc7446 |
14 | 144951ad00a1 |
15 | 92e27b0ce1d |
hex | 4d2b671c6dd |
5303050553053 has 4 divisors (see below), whose sum is σ = 5785146057888. Its totient is φ = 4820955048220.
The previous prime is 5303050553039. The next prime is 5303050553083. The reversal of 5303050553053 is 3503550503035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5303050553053 - 213 = 5303050544861 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303050553083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241047752401 + ... + 241047752422.
It is an arithmetic number, because the mean of its divisors is an integer number (1446286514472).
Almost surely, 25303050553053 is an apocalyptic number.
It is an amenable number.
5303050553053 is a deficient number, since it is larger than the sum of its proper divisors (482095504835).
5303050553053 is a wasteful number, since it uses less digits than its factorization.
5303050553053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 482095504834.
The product of its (nonzero) digits is 253125, while the sum is 37.
The spelling of 5303050553053 in words is "five trillion, three hundred three billion, fifty million, five hundred fifty-three thousand, fifty-three".
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