53030511433 has 8 divisors (see below), whose sum is σ = 56270197152. Its totient is φ = 49804186176.

The previous prime is 53030511421. The next prime is 53030511481. The reversal of 53030511433 is 33411503035.

53030511433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53030511433 - 2²⁵ = 52996957001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53030511403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3331935 + ... + 3347812.

It is an arithmetic number, because the mean of its divisors is an integer number (7033774644).

Almost surely, 2^53030511433 is an apocalyptic number.

It is an amenable number.

53030511433 is a deficient number, since it is larger than the sum of its proper divisors (3239685719).

53030511433 is a wasteful number, since it uses less digits than its factorization.

53030511433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6680231.

The product of its (nonzero) digits is 8100, while the sum is 28.

The spelling of 53030511433 in words is "fifty-three billion, thirty million, five hundred eleven thousand, four hundred thirty-three".