Base | Representation |
---|---|
bin | 110001011000110111… |
… | …010110001101111001 |
3 | 12001212210021002211211 |
4 | 301120313112031321 |
5 | 1332101302331411 |
6 | 40210055523121 |
7 | 3555100624123 |
oct | 613067261571 |
9 | 161783232754 |
10 | 53030511481 |
11 | 205433831a2 |
12 | a33b9894a1 |
13 | 5001877c9c |
14 | 27d0dda213 |
15 | 15a5964221 |
hex | c58dd6379 |
53030511481 has 2 divisors, whose sum is σ = 53030511482. Its totient is φ = 53030511480.
The previous prime is 53030511421. The next prime is 53030511497. The reversal of 53030511481 is 18411503035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52048315881 + 982195600 = 228141^2 + 31340^2 .
It is a cyclic number.
It is not a de Polignac number, because 53030511481 - 219 = 53029987193 is a prime.
It is a super-2 number, since 2×530305114812 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53030511421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26515255740 + 26515255741.
It is an arithmetic number, because the mean of its divisors is an integer number (26515255741).
Almost surely, 253030511481 is an apocalyptic number.
It is an amenable number.
53030511481 is a deficient number, since it is larger than the sum of its proper divisors (1).
53030511481 is an equidigital number, since it uses as much as digits as its factorization.
53030511481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 53030511481 in words is "fifty-three billion, thirty million, five hundred eleven thousand, four hundred eighty-one".
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