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5303134104101 = 5975938874157
BaseRepresentation
bin100110100101011101101…
…1011001010101000100101
3200202222022112102010201222
41031022323123022220211
51143341304312312401
615140120504230125
71055065415063321
oct115127333125045
920688275363658
105303134104101
111765056a49639
12717948a6b345
132c61112cbc32
1414495cc3c981
1592e30113c1b
hex4d2bb6caa25

5303134104101 has 4 divisors (see below), whose sum is σ = 5303143575852. Its totient is φ = 5303124632352.

The previous prime is 5303134104053. The next prime is 5303134104131. The reversal of 5303134104101 is 1014014313035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5151088699201 + 152045404900 = 2269601^2 + 389930^2 .

It is a cyclic number.

It is not a de Polignac number, because 5303134104101 - 222 = 5303129909797 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5303134104131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3839486 + ... + 5034671.

It is an arithmetic number, because the mean of its divisors is an integer number (1325785893963).

Almost surely, 25303134104101 is an apocalyptic number.

It is an amenable number.

5303134104101 is a deficient number, since it is larger than the sum of its proper divisors (9471751).

5303134104101 is an equidigital number, since it uses as much as digits as its factorization.

5303134104101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9471750.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 5303134104101 its reverse (1014014313035), we get a palindrome (6317148417136).

The spelling of 5303134104101 in words is "five trillion, three hundred three billion, one hundred thirty-four million, one hundred four thousand, one hundred one".

Divisors: 1 597593 8874157 5303134104101