Base | Representation |
---|---|
bin | 1111011011110010011… |
… | …01000001101011111011 |
3 | 1212200211112011120210100 |
4 | 13231321031001223323 |
5 | 32142040443412243 |
6 | 1043342330450443 |
7 | 53212454216301 |
oct | 7557115015373 |
9 | 1780745146710 |
10 | 530314435323 |
11 | 1949a5745432 |
12 | 86941293a23 |
13 | 3b0156c627a |
14 | 1b94b31c271 |
15 | dbdc16d0d3 |
hex | 7b79341afb |
530314435323 has 12 divisors (see below), whose sum is σ = 766248935400. Its totient is φ = 353432558976.
The previous prime is 530314435309. The next prime is 530314435333. The reversal of 530314435323 is 323534413035.
530314435323 is a `hidden beast` number, since 53 + 0 + 31 + 4 + 43 + 532 + 3 = 666.
It is not a de Polignac number, because 530314435323 - 25 = 530314435291 is a prime.
It is a super-2 number, since 2×5303144353232 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (530314435333) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9169398 + ... + 9227051.
It is an arithmetic number, because the mean of its divisors is an integer number (63854077950).
Almost surely, 2530314435323 is an apocalyptic number.
530314435323 is a deficient number, since it is larger than the sum of its proper divisors (235934500077).
530314435323 is a wasteful number, since it uses less digits than its factorization.
530314435323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18399658 (or 18399655 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 36.
Adding to 530314435323 its reverse (323534413035), we get a palindrome (853848848358).
The spelling of 530314435323 in words is "five hundred thirty billion, three hundred fourteen million, four hundred thirty-five thousand, three hundred twenty-three".
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