530314435333 has 2 divisors, whose sum is σ = 530314435334. Its totient is φ = 530314435332.

The previous prime is 530314435309. The next prime is 530314435337. The reversal of 530314435333 is 333534413035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 281496035844 + 248818399489 = 530562^2 + 498817^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-530314435333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530314435292 and 530314435301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530314435337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265157217666 + 265157217667.

It is an arithmetic number, because the mean of its divisors is an integer number (265157217667).

Almost surely, 2^530314435333 is an apocalyptic number.

It is an amenable number.

530314435333 is a deficient number, since it is larger than the sum of its proper divisors (1).

530314435333 is an equidigital number, since it uses as much as digits as its factorization.

530314435333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 37.

Adding to 530314435333 its reverse (333534413035), we get a palindrome (863848848368).

The spelling of 530314435333 in words is "five hundred thirty billion, three hundred fourteen million, four hundred thirty-five thousand, three hundred thirty-three".