Base | Representation |
---|---|
bin | 100110100101100000110… |
… | …1111111100011011101011 |
3 | 200202222120221002002111112 |
4 | 1031023001233330123223 |
5 | 1143342013443324001 |
6 | 15140135214420535 |
7 | 1055101144024340 |
oct | 115130157743353 |
9 | 20688527062445 |
10 | 5303240214251 |
11 | 1765100933781 |
12 | 71797850174b |
13 | 2c612a2a18c5 |
14 | 14496cd807c7 |
15 | 92e395c3cbb |
hex | 4d2c1bfc6eb |
5303240214251 has 4 divisors (see below), whose sum is σ = 6060845959152. Its totient is φ = 4545634469352.
The previous prime is 5303240214169. The next prime is 5303240214277. The reversal of 5303240214251 is 1524120423035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5303240214251 - 242 = 905193703147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5303240214281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378802872440 + ... + 378802872453.
It is an arithmetic number, because the mean of its divisors is an integer number (1515211489788).
Almost surely, 25303240214251 is an apocalyptic number.
5303240214251 is a deficient number, since it is larger than the sum of its proper divisors (757605744901).
5303240214251 is an equidigital number, since it uses as much as digits as its factorization.
5303240214251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 757605744900.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 5303240214251 its reverse (1524120423035), we get a palindrome (6827360637286).
The spelling of 5303240214251 in words is "five trillion, three hundred three billion, two hundred forty million, two hundred fourteen thousand, two hundred fifty-one".
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