Base | Representation |
---|---|
bin | 110001011000111110… |
… | …101101110001111101 |
3 | 12001212220220020101202 |
4 | 301120332231301331 |
5 | 1332102301134010 |
6 | 40210205145245 |
7 | 3555123220313 |
oct | 613076556175 |
9 | 161786806352 |
10 | 53032443005 |
11 | 205444823a3 |
12 | a34055b225 |
13 | 50020a31b9 |
14 | 27d13800b3 |
15 | 15a5be66a5 |
hex | c58fadc7d |
53032443005 has 4 divisors (see below), whose sum is σ = 63638931612. Its totient is φ = 42425954400.
The previous prime is 53032443001. The next prime is 53032443029. The reversal of 53032443005 is 50034423035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 25832847076 + 27199595929 = 160726^2 + 164923^2 .
It is not a de Polignac number, because 53032443005 - 22 = 53032443001 is a prime.
It is a super-2 number, since 2×530324430052 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53032443001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303244296 + ... + 5303244305.
It is an arithmetic number, because the mean of its divisors is an integer number (15909732903).
Almost surely, 253032443005 is an apocalyptic number.
It is an amenable number.
53032443005 is a deficient number, since it is larger than the sum of its proper divisors (10606488607).
53032443005 is a wasteful number, since it uses less digits than its factorization.
53032443005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10606488606.
The product of its (nonzero) digits is 21600, while the sum is 29.
The spelling of 53032443005 in words is "fifty-three billion, thirty-two million, four hundred forty-three thousand, five".
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