Base | Representation |
---|---|
bin | 110001011001000001… |
… | …000111100110001011 |
3 | 12001212222002020122012 |
4 | 301121001013212023 |
5 | 1332102431314120 |
6 | 40210230450135 |
7 | 3555131453165 |
oct | 613101074613 |
9 | 161788066565 |
10 | 53033073035 |
11 | 20544872788 |
12 | a34080394b |
13 | 5002263bb7 |
14 | 27d14a5935 |
15 | 15a5cbd1c5 |
hex | c5904798b |
53033073035 has 4 divisors (see below), whose sum is σ = 63639687648. Its totient is φ = 42426458424.
The previous prime is 53033072999. The next prime is 53033073059. The reversal of 53033073035 is 53037033035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53033073035 - 26 = 53033072971 is a prime.
It is a super-2 number, since 2×530330730352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53033072992 and 53033073010.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5303307299 + ... + 5303307308.
It is an arithmetic number, because the mean of its divisors is an integer number (15909921912).
Almost surely, 253033073035 is an apocalyptic number.
53033073035 is a deficient number, since it is larger than the sum of its proper divisors (10606614613).
53033073035 is a wasteful number, since it uses less digits than its factorization.
53033073035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10606614612.
The product of its (nonzero) digits is 42525, while the sum is 32.
The spelling of 53033073035 in words is "fifty-three billion, thirty-three million, seventy-three thousand, thirty-five".
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