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530334555541 = 7143952649117
BaseRepresentation
bin1111011011110100110…
…01110001110110010101
31212200212221000210112121
413231322121301312111
532142111121234131
61043344330015541
753213120225650
oct7557231616625
91780787023477
10530334555541
11194a0603800a
1286947b775b1
133b01991c31b
141b94dc78897
15dbddce4911
hex7b7a671d95

530334555541 has 8 divisors (see below), whose sum is σ = 606517839360. Its totient is φ = 454256572848.

The previous prime is 530334555539. The next prime is 530334555577. The reversal of 530334555541 is 145555433035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 530334555541 - 21 = 530334555539 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530334555521) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26314486 + ... + 26334631.

It is an arithmetic number, because the mean of its divisors is an integer number (75814729920).

Almost surely, 2530334555541 is an apocalyptic number.

It is an amenable number.

530334555541 is a deficient number, since it is larger than the sum of its proper divisors (76183283819).

530334555541 is a wasteful number, since it uses less digits than its factorization.

530334555541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52650563.

The product of its (nonzero) digits is 1350000, while the sum is 43.

Adding to 530334555541 its reverse (145555433035), we get a palindrome (675889988576).

The spelling of 530334555541 in words is "five hundred thirty billion, three hundred thirty-four million, five hundred fifty-five thousand, five hundred forty-one".

Divisors: 1 7 1439 10073 52649117 368543819 75762079363 530334555541