Base | Representation |
---|---|
bin | 1111011011110101011… |
… | …11101001100010001011 |
3 | 1212200220022211001220000 |
4 | 13231322233221202023 |
5 | 32142114103214101 |
6 | 1043345052534043 |
7 | 53213220034365 |
oct | 7557257514213 |
9 | 1780808731800 |
10 | 530340288651 |
11 | 194a092a3418 |
12 | 86949a81323 |
13 | 3b01ab789b4 |
14 | 1b95092bd35 |
15 | dbde578486 |
hex | 7b7abe988b |
530340288651 has 10 divisors (see below), whose sum is σ = 792236727612. Its totient is φ = 353560192380.
The previous prime is 530340288593. The next prime is 530340288659. The reversal of 530340288651 is 156882043035.
530340288651 is a `hidden beast` number, since 5 + 303 + 4 + 0 + 288 + 65 + 1 = 666.
It is not a de Polignac number, because 530340288651 - 215 = 530340255883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530340288597 and 530340288606.
It is not an unprimeable number, because it can be changed into a prime (530340288659) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 3273705405 + ... + 3273705566.
Almost surely, 2530340288651 is an apocalyptic number.
530340288651 is a deficient number, since it is larger than the sum of its proper divisors (261896438961).
530340288651 is an equidigital number, since it uses as much as digits as its factorization.
530340288651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6547410983 (or 6547410974 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 45.
The spelling of 530340288651 in words is "five hundred thirty billion, three hundred forty million, two hundred eighty-eight thousand, six hundred fifty-one".
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