Base | Representation |
---|---|
bin | 110001011001000101… |
… | …010010001000000111 |
3 | 12001220001010201011211 |
4 | 301121011102020013 |
5 | 1332103221232433 |
6 | 40210310112251 |
7 | 3555143651050 |
oct | 613105221007 |
9 | 161801121154 |
10 | 53034164743 |
11 | 20545448a1a |
12 | a34104b687 |
13 | 5002556a91 |
14 | 27d16ab727 |
15 | 15a5e368cd |
hex | c59152207 |
53034164743 has 8 divisors (see below), whose sum is σ = 60851952000. Its totient is φ = 45276747000.
The previous prime is 53034164741. The next prime is 53034164747. The reversal of 53034164743 is 34746143035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53034164743 - 21 = 53034164741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53034164696 and 53034164705.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53034164741) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15090493 + ... + 15094006.
It is an arithmetic number, because the mean of its divisors is an integer number (7606494000).
Almost surely, 253034164743 is an apocalyptic number.
53034164743 is a deficient number, since it is larger than the sum of its proper divisors (7817787257).
53034164743 is a wasteful number, since it uses less digits than its factorization.
53034164743 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30184757.
The product of its (nonzero) digits is 362880, while the sum is 40.
The spelling of 53034164743 in words is "fifty-three billion, thirty-four million, one hundred sixty-four thousand, seven hundred forty-three".
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