Base | Representation |
---|---|
bin | 100110100101100110010… |
… | …1101000010010011011011 |
3 | 200210000001201220102212011 |
4 | 1031023030231002103123 |
5 | 1143342403021014433 |
6 | 15140205341530351 |
7 | 1055105535134434 |
oct | 115131455022333 |
9 | 20700051812764 |
10 | 5303424001243 |
11 | 1765195652655 |
12 | 717a09b739b7 |
13 | 2c61593a03c4 |
14 | 14498954248b |
15 | 92e4a7c93cd |
hex | 4d2ccb424db |
5303424001243 has 4 divisors (see below), whose sum is σ = 5303533441528. Its totient is φ = 5303314560960.
The previous prime is 5303424001231. The next prime is 5303424001261. The reversal of 5303424001243 is 3421004243035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5303424001243 - 213 = 5303423993051 is a prime.
It is a super-2 number, since 2×53034240012432 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5303424001283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54647421 + ... + 54744382.
It is an arithmetic number, because the mean of its divisors is an integer number (1325883360382).
Almost surely, 25303424001243 is an apocalyptic number.
5303424001243 is a deficient number, since it is larger than the sum of its proper divisors (109440285).
5303424001243 is a wasteful number, since it uses less digits than its factorization.
5303424001243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109440284.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 5303424001243 its reverse (3421004243035), we get a palindrome (8724428244278).
The spelling of 5303424001243 in words is "five trillion, three hundred three billion, four hundred twenty-four million, one thousand, two hundred forty-three".
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