Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1100000011101110001001 |
3 | 200210000002022012121020100 |
4 | 1031023031030003232021 |
5 | 1143342412111233023 |
6 | 15140210232120013 |
7 | 1055105664224613 |
oct | 115131514035611 |
9 | 20700068177210 |
10 | 5303432133513 |
11 | 176519a1a7538 |
12 | 717a10836009 |
13 | 2c615ac89ab7 |
14 | 14498a65bdb3 |
15 | 92e4b383c43 |
hex | 4d2cd303b89 |
5303432133513 has 24 divisors (see below), whose sum is σ = 8538033160800. Its totient is φ = 3152504548224.
The previous prime is 5303432133481. The next prime is 5303432133541. The reversal of 5303432133513 is 3153312343035.
5303432133513 is a `hidden beast` number, since 5 + 3 + 0 + 3 + 4 + 3 + 2 + 133 + 513 = 666.
It is not a de Polignac number, because 5303432133513 - 25 = 5303432133481 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5303430133513) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 912180123 + ... + 912185936.
It is an arithmetic number, because the mean of its divisors is an integer number (355751381700).
Almost surely, 25303432133513 is an apocalyptic number.
It is an amenable number.
5303432133513 is a deficient number, since it is larger than the sum of its proper divisors (3234601027287).
5303432133513 is a wasteful number, since it uses less digits than its factorization.
5303432133513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1824366101 (or 1824366098 counting only the distinct ones).
The product of its (nonzero) digits is 145800, while the sum is 36.
Adding to 5303432133513 its reverse (3153312343035), we get a palindrome (8456744476548).
The spelling of 5303432133513 in words is "five trillion, three hundred three billion, four hundred thirty-two million, one hundred thirty-three thousand, five hundred thirteen".
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