Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1100100000101010001100 |
3 | 200210000002022102121211101 |
4 | 1031023031030200222030 |
5 | 1143342412124031134 |
6 | 15140210234432444 |
7 | 1055105665230313 |
oct | 115131514405214 |
9 | 20700068377741 |
10 | 5303432252044 |
11 | 176519a2785a3 |
12 | 717a10892724 |
13 | 2c615accba34 |
14 | 14498a68d27a |
15 | 92e4b3a8e14 |
hex | 4d2cd320a8c |
5303432252044 has 12 divisors (see below), whose sum is σ = 9531844453264. Its totient is φ = 2580048122544.
The previous prime is 5303432252029. The next prime is 5303432252077. The reversal of 5303432252044 is 4402522343035.
It is a super-3 number, since 3×53034322520443 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a junction number, because it is equal to n+sod(n) for n = 5303432251994 and 5303432252012.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17917000704 + ... + 17917000999.
Almost surely, 25303432252044 is an apocalyptic number.
It is an amenable number.
5303432252044 is a deficient number, since it is larger than the sum of its proper divisors (4228412201220).
5303432252044 is a wasteful number, since it uses less digits than its factorization.
5303432252044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35834001744 (or 35834001742 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 37.
Adding to 5303432252044 its reverse (4402522343035), we get a palindrome (9705954595079).
Subtracting from 5303432252044 its reverse (4402522343035), we obtain a palindrome (900909909009).
The spelling of 5303432252044 in words is "five trillion, three hundred three billion, four hundred thirty-two million, two hundred fifty-two thousand, forty-four".
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