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5303432252044 = 223735834001703
BaseRepresentation
bin100110100101100110100…
…1100100000101010001100
3200210000002022102121211101
41031023031030200222030
51143342412124031134
615140210234432444
71055105665230313
oct115131514405214
920700068377741
105303432252044
11176519a2785a3
12717a10892724
132c615accba34
1414498a68d27a
1592e4b3a8e14
hex4d2cd320a8c

5303432252044 has 12 divisors (see below), whose sum is σ = 9531844453264. Its totient is φ = 2580048122544.

The previous prime is 5303432252029. The next prime is 5303432252077. The reversal of 5303432252044 is 4402522343035.

It is a super-3 number, since 3×53034322520443 (a number of 39 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (37).

It is a junction number, because it is equal to n+sod(n) for n = 5303432251994 and 5303432252012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17917000704 + ... + 17917000999.

Almost surely, 25303432252044 is an apocalyptic number.

It is an amenable number.

5303432252044 is a deficient number, since it is larger than the sum of its proper divisors (4228412201220).

5303432252044 is a wasteful number, since it uses less digits than its factorization.

5303432252044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35834001744 (or 35834001742 counting only the distinct ones).

The product of its (nonzero) digits is 345600, while the sum is 37.

Adding to 5303432252044 its reverse (4402522343035), we get a palindrome (9705954595079).

Subtracting from 5303432252044 its reverse (4402522343035), we obtain a palindrome (900909909009).

The spelling of 5303432252044 in words is "five trillion, three hundred three billion, four hundred thirty-two million, two hundred fifty-two thousand, forty-four".

Divisors: 1 2 4 37 74 148 35834001703 71668003406 143336006812 1325858063011 2651716126022 5303432252044