Base | Representation |
---|---|
bin | 100110100101100110100… |
… | …1100110110110111111011 |
3 | 200210000002022121020122102 |
4 | 1031023031030312313323 |
5 | 1143342412134434120 |
6 | 15140210240414015 |
7 | 1055105666056511 |
oct | 115131514666773 |
9 | 20700068536572 |
10 | 5303432343035 |
11 | 176519a32a9a2 |
12 | 717a1091730b |
13 | 2c615b031288 |
14 | 14498a6b44b1 |
15 | 92e4b3c5d75 |
hex | 4d2cd336dfb |
5303432343035 has 4 divisors (see below), whose sum is σ = 6364118811648. Its totient is φ = 4242745874424.
The previous prime is 5303432342983. The next prime is 5303432343067.
5303432343035 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5303432343035 - 214 = 5303432326651 is a prime.
It is a super-2 number, since 2×53034323430352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5303432343035.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530343234299 + ... + 530343234308.
It is an arithmetic number, because the mean of its divisors is an integer number (1591029702912).
Almost surely, 25303432343035 is an apocalyptic number.
5303432343035 is a deficient number, since it is larger than the sum of its proper divisors (1060686468613).
5303432343035 is a wasteful number, since it uses less digits than its factorization.
5303432343035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1060686468612.
The product of its (nonzero) digits is 583200, while the sum is 38.
The spelling of 5303432343035 in words is "five trillion, three hundred three billion, four hundred thirty-two million, three hundred forty-three thousand, thirty-five".
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