Base | Representation |
---|---|
bin | 100110100101101000110… |
… | …0011101001001011001111 |
3 | 200210000021102010012101200 |
4 | 1031023101203221023033 |
5 | 1143343034342100403 |
6 | 15140221411040543 |
7 | 1055110544210664 |
oct | 115132143511317 |
9 | 20700242105350 |
10 | 5303505425103 |
11 | 17652276065a6 |
12 | 717a312a0153 |
13 | 2c617020b8c2 |
14 | 144996299a6b |
15 | 92e52a0eca3 |
hex | 4d2d18e92cf |
5303505425103 has 12 divisors (see below), whose sum is σ = 8111243591568. Its totient is φ = 3327689678400.
The previous prime is 5303505425089. The next prime is 5303505425111. The reversal of 5303505425103 is 3015245053035.
5303505425103 is a `hidden beast` number, since 5 + 3 + 0 + 3 + 5 + 0 + 542 + 5 + 103 = 666.
It is not a de Polignac number, because 5303505425103 - 210 = 5303505424079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303505425203) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17331716923 + ... + 17331717228.
It is an arithmetic number, because the mean of its divisors is an integer number (675936965964).
Almost surely, 25303505425103 is an apocalyptic number.
5303505425103 is a deficient number, since it is larger than the sum of its proper divisors (2807738166465).
5303505425103 is a wasteful number, since it uses less digits than its factorization.
5303505425103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34663434174 (or 34663434171 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 36.
The spelling of 5303505425103 in words is "five trillion, three hundred three billion, five hundred five million, four hundred twenty-five thousand, one hundred three".
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