Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1011011001011010110111 |
3 | 200210000100220002012122111 |
4 | 1031023103223121122313 |
5 | 1143343122444342101 |
6 | 15140225121511451 |
7 | 1055111455536214 |
oct | 115132353313267 |
9 | 20700326065574 |
10 | 5303541012151 |
11 | 1765245702688 |
12 | 717a411a2587 |
13 | 2c61776bb925 |
14 | 14499acc0b0b |
15 | 92e55bde251 |
hex | 4d2d3ad96b7 |
5303541012151 has 8 divisors (see below), whose sum is σ = 5356756190304. Its totient is φ = 5250339655200.
The previous prime is 5303541012103. The next prime is 5303541012173. The reversal of 5303541012151 is 1512101453035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5303541012151 - 227 = 5303406794423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303541012191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2683140 + ... + 4219753.
It is an arithmetic number, because the mean of its divisors is an integer number (669594523788).
Almost surely, 25303541012151 is an apocalyptic number.
5303541012151 is a deficient number, since it is larger than the sum of its proper divisors (53215178153).
5303541012151 is a wasteful number, since it uses less digits than its factorization.
5303541012151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6910601.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 5303541012151 its reverse (1512101453035), we get a palindrome (6815642465186).
The spelling of 5303541012151 in words is "five trillion, three hundred three billion, five hundred forty-one million, twelve thousand, one hundred fifty-one".
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