Base | Representation |
---|---|
bin | 111100010010110110000011… |
… | …1000111100010111011100101 |
3 | 2120112211111102021111020210210 |
4 | 1320211230013013202323211 |
5 | 1024003321144400434230 |
6 | 5115545552235010033 |
7 | 216465632223055542 |
oct | 17045540707427345 |
9 | 2515744367436723 |
10 | 530355566030565 |
11 | 143a95594757330 |
12 | 4b596565b99919 |
13 | 199c1413894062 |
14 | 94d74bc59dbc9 |
15 | 414ab731deeb0 |
hex | 1e25b071e2ee5 |
530355566030565 has 16 divisors (see below), whose sum is σ = 925711533435456. Its totient is φ = 257142092620800.
The previous prime is 530355566030533. The next prime is 530355566030573. The reversal of 530355566030565 is 565030665553035.
It is not a de Polignac number, because 530355566030565 - 25 = 530355566030533 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1607138078716 + ... + 1607138079045.
It is an arithmetic number, because the mean of its divisors is an integer number (57856970839716).
Almost surely, 2530355566030565 is an apocalyptic number.
530355566030565 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
530355566030565 is a deficient number, since it is larger than the sum of its proper divisors (395355967404891).
530355566030565 is a wasteful number, since it uses less digits than its factorization.
530355566030565 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3214276157780.
The product of its (nonzero) digits is 91125000, while the sum is 57.
The spelling of 530355566030565 in words is "five hundred thirty trillion, three hundred fifty-five billion, five hundred sixty-six million, thirty thousand, five hundred sixty-five".
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