Base | Representation |
---|---|
bin | 11000000111100011111110… |
… | …00101101010101100011010 |
3 | 20221210020012002112220120101 |
4 | 30003301333011222230122 |
5 | 23422422010410104114 |
6 | 304444325213450014 |
7 | 14112516100566166 |
oct | 1403617705525432 |
9 | 227706162486511 |
10 | 53036388363034 |
11 | 1599867363656a |
12 | 5b469831a090a |
13 | 2379404cac62b |
14 | d14d9116dca6 |
15 | 61e8e8c7ad74 |
hex | 303c7f16ab1a |
53036388363034 has 4 divisors (see below), whose sum is σ = 79554582544554. Its totient is φ = 26518194181516.
The previous prime is 53036388363031. The next prime is 53036388363053. The reversal of 53036388363034 is 43036388363035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 48470794637409 + 4565593725625 = 6962097^2 + 2136725^2 .
It is not an unprimeable number, because it can be changed into a prime (53036388363031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13259097090757 + ... + 13259097090760.
Almost surely, 253036388363034 is an apocalyptic number.
53036388363034 is a deficient number, since it is larger than the sum of its proper divisors (26518194181520).
53036388363034 is a wasteful number, since it uses less digits than its factorization.
53036388363034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26518194181519.
The product of its (nonzero) digits is 33592320, while the sum is 55.
Subtracting from 53036388363034 its reverse (43036388363035), we obtain a palindrome (9999999999999).
The spelling of 53036388363034 in words is "fifty-three trillion, thirty-six billion, three hundred eighty-eight million, three hundred sixty-three thousand, thirty-four".
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