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530373535493 = 3967133696379
BaseRepresentation
bin1111011011111001011…
…10011110011100000101
31212200222122101011222112
413231330232132130011
532142201111113433
61043352241310405
753214102445064
oct7557456363405
91780878334875
10530373535493
11194a2604124a
1286959035405
133b024a19799
141b9551041db
15dbe2444348
hex7b7cb9e705

530373535493 has 4 divisors (see below), whose sum is σ = 530507235840. Its totient is φ = 530239835148.

The previous prime is 530373535477. The next prime is 530373535499. The reversal of 530373535493 is 394535373035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530373535493 - 24 = 530373535477 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530373535499) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66844223 + ... + 66852156.

It is an arithmetic number, because the mean of its divisors is an integer number (132626808960).

Almost surely, 2530373535493 is an apocalyptic number.

It is an amenable number.

530373535493 is a deficient number, since it is larger than the sum of its proper divisors (133700347).

530373535493 is a wasteful number, since it uses less digits than its factorization.

530373535493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 133700346.

The product of its (nonzero) digits is 7654500, while the sum is 50.

The spelling of 530373535493 in words is "five hundred thirty billion, three hundred seventy-three million, five hundred thirty-five thousand, four hundred ninety-three".

Divisors: 1 3967 133696379 530373535493