Search a number
-
+
5303841 = 31767947
BaseRepresentation
bin10100001110111000100001
3100222110111120
4110032320201
52324210331
6305402453
763040044
oct24167041
910873446
105303841
112aa2944
121939429
13113918a
149c0c5b
156eb796
hex50ee21

5303841 has 4 divisors (see below), whose sum is σ = 7071792. Its totient is φ = 3535892.

The previous prime is 5303827. The next prime is 5303849. The reversal of 5303841 is 1483035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5303841 - 27 = 5303713 is a prime.

It is a D-number.

It is not an unprimeable number, because it can be changed into a prime (5303849) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 883971 + ... + 883976.

It is an arithmetic number, because the mean of its divisors is an integer number (1767948).

Almost surely, 25303841 is an apocalyptic number.

It is an amenable number.

5303841 is a deficient number, since it is larger than the sum of its proper divisors (1767951).

5303841 is a wasteful number, since it uses less digits than its factorization.

5303841 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1767950.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 5303841 is about 2303.0069474494. The cubic root of 5303841 is about 174.3934484149.

Adding to 5303841 its reverse (1483035), we get a palindrome (6786876).

It can be divided in two parts, 530 and 3841, that added together give a triangular number (4371 = T93).

The spelling of 5303841 in words is "five million, three hundred three thousand, eight hundred forty-one".

Divisors: 1 3 1767947 5303841