Base | Representation |
---|---|
bin | 1111011011111100100… |
… | …11101010011101000011 |
3 | 1212201001111021211111000 |
4 | 13231332103222131003 |
5 | 32142224403430001 |
6 | 1043355030023043 |
7 | 53214544063464 |
oct | 7557623523503 |
9 | 1781044254430 |
10 | 530400061251 |
11 | 194a3a009465 |
12 | 86965aa7a83 |
13 | 3b02a3762b8 |
14 | 1b95884ad6b |
15 | dbe4933a86 |
hex | 7b7e4ea743 |
530400061251 has 32 divisors (see below), whose sum is σ = 832612392000. Its totient is φ = 332555120640.
The previous prime is 530400061241. The next prime is 530400061271. The reversal of 530400061251 is 152160004035.
530400061251 is a `hidden beast` number, since 5 + 3 + 0 + 40 + 0 + 0 + 612 + 5 + 1 = 666.
It is not a de Polignac number, because 530400061251 - 230 = 529326319427 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (530400061241) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 200175 + ... + 1049223.
It is an arithmetic number, because the mean of its divisors is an integer number (26019137250).
Almost surely, 2530400061251 is an apocalyptic number.
530400061251 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
530400061251 is a deficient number, since it is larger than the sum of its proper divisors (302212330749).
530400061251 is a wasteful number, since it uses less digits than its factorization.
530400061251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 850436 (or 850430 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 530400061251 its reverse (152160004035), we get a palindrome (682560065286).
The spelling of 530400061251 in words is "five hundred thirty billion, four hundred million, sixty-one thousand, two hundred fifty-one".
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