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530400061253 = 2232378475611
BaseRepresentation
bin1111011011111100100…
…11101010011101000101
31212201001111021211111002
413231332103222131011
532142224403430003
61043355030023045
753214544063466
oct7557623523505
91781044254432
10530400061253
11194a3a009467
1286965aa7a85
133b02a3762ba
141b95884ad6d
15dbe4933a88
hex7b7e4ea745

530400061253 has 4 divisors (see below), whose sum is σ = 532778537088. Its totient is φ = 528021585420.

The previous prime is 530400061241. The next prime is 530400061271. The reversal of 530400061253 is 352160004035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 530400061253 - 212 = 530400057157 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530400061283) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1189237583 + ... + 1189238028.

It is an arithmetic number, because the mean of its divisors is an integer number (133194634272).

Almost surely, 2530400061253 is an apocalyptic number.

It is an amenable number.

530400061253 is a deficient number, since it is larger than the sum of its proper divisors (2378475835).

530400061253 is a wasteful number, since it uses less digits than its factorization.

530400061253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2378475834.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 530400061253 its reverse (352160004035), we get a palindrome (882560065288).

The spelling of 530400061253 in words is "five hundred thirty billion, four hundred million, sixty-one thousand, two hundred fifty-three".

Divisors: 1 223 2378475611 530400061253