Base | Representation |
---|---|
bin | 1111011011111100100… |
… | …11101010011101000101 |
3 | 1212201001111021211111002 |
4 | 13231332103222131011 |
5 | 32142224403430003 |
6 | 1043355030023045 |
7 | 53214544063466 |
oct | 7557623523505 |
9 | 1781044254432 |
10 | 530400061253 |
11 | 194a3a009467 |
12 | 86965aa7a85 |
13 | 3b02a3762ba |
14 | 1b95884ad6d |
15 | dbe4933a88 |
hex | 7b7e4ea745 |
530400061253 has 4 divisors (see below), whose sum is σ = 532778537088. Its totient is φ = 528021585420.
The previous prime is 530400061241. The next prime is 530400061271. The reversal of 530400061253 is 352160004035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 530400061253 - 212 = 530400057157 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530400061283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1189237583 + ... + 1189238028.
It is an arithmetic number, because the mean of its divisors is an integer number (133194634272).
Almost surely, 2530400061253 is an apocalyptic number.
It is an amenable number.
530400061253 is a deficient number, since it is larger than the sum of its proper divisors (2378475835).
530400061253 is a wasteful number, since it uses less digits than its factorization.
530400061253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2378475834.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 530400061253 its reverse (352160004035), we get a palindrome (882560065288).
The spelling of 530400061253 in words is "five hundred thirty billion, four hundred million, sixty-one thousand, two hundred fifty-three".
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