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530400341341 = 13192239629461
BaseRepresentation
bin1111011011111100101…
…00101110110101011101
31212201001111211001200201
413231332110232311131
532142224441410331
61043355040023501
753214546341203
oct7557624566535
91781044731621
10530400341341
11194a3a18a942
1286966001b91
133b02a443930
141b9588c1073
15dbe498ba61
hex7b7e52ed5d

530400341341 has 16 divisors (see below), whose sum is σ = 603959856640. Its totient is φ = 461751865920.

The previous prime is 530400341329. The next prime is 530400341351. The reversal of 530400341341 is 143143004035.

It is a cyclic number.

It is not a de Polignac number, because 530400341341 - 217 = 530400210269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530400341351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4759650 + ... + 4869811.

It is an arithmetic number, because the mean of its divisors is an integer number (37747491040).

Almost surely, 2530400341341 is an apocalyptic number.

It is an amenable number.

530400341341 is a deficient number, since it is larger than the sum of its proper divisors (73559515299).

530400341341 is a wasteful number, since it uses less digits than its factorization.

530400341341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9629716.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 530400341341 its reverse (143143004035), we get a palindrome (673543345376).

It can be divided in two parts, 5304003 and 41341, that added together give a square (5345344 = 23122).

The spelling of 530400341341 in words is "five hundred thirty billion, four hundred million, three hundred forty-one thousand, three hundred forty-one".

Divisors: 1 13 19 223 247 2899 4237 55081 9629461 125182993 182959759 2147369803 2378476867 27915807439 40800026257 530400341341