Base | Representation |
---|---|
bin | 1111011011111100101… |
… | …00101110110101011101 |
3 | 1212201001111211001200201 |
4 | 13231332110232311131 |
5 | 32142224441410331 |
6 | 1043355040023501 |
7 | 53214546341203 |
oct | 7557624566535 |
9 | 1781044731621 |
10 | 530400341341 |
11 | 194a3a18a942 |
12 | 86966001b91 |
13 | 3b02a443930 |
14 | 1b9588c1073 |
15 | dbe498ba61 |
hex | 7b7e52ed5d |
530400341341 has 16 divisors (see below), whose sum is σ = 603959856640. Its totient is φ = 461751865920.
The previous prime is 530400341329. The next prime is 530400341351. The reversal of 530400341341 is 143143004035.
It is a cyclic number.
It is not a de Polignac number, because 530400341341 - 217 = 530400210269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530400341351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4759650 + ... + 4869811.
It is an arithmetic number, because the mean of its divisors is an integer number (37747491040).
Almost surely, 2530400341341 is an apocalyptic number.
It is an amenable number.
530400341341 is a deficient number, since it is larger than the sum of its proper divisors (73559515299).
530400341341 is a wasteful number, since it uses less digits than its factorization.
530400341341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9629716.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 530400341341 its reverse (143143004035), we get a palindrome (673543345376).
It can be divided in two parts, 5304003 and 41341, that added together give a square (5345344 = 23122).
The spelling of 530400341341 in words is "five hundred thirty billion, four hundred million, three hundred forty-one thousand, three hundred forty-one".
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