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5304014232351 = 311091594233313
BaseRepresentation
bin100110100101110111111…
…1000100101101100011111
3200210001120212112021201120
41031023233320211230133
51143400110120413401
615140344104342023
71055126263046022
oct115135770455437
920701525467646
105304014232351
111765468838a5a
12717b53774913
132c6221758693
14144a03aa51b9
1592e82517836
hex4d2efe25b1f

5304014232351 has 8 divisors (see below), whose sum is σ = 7078395914160. Its totient is φ = 3532821019392.

The previous prime is 5304014232347. The next prime is 5304014232353. The reversal of 5304014232351 is 1532324104035.

5304014232351 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5304014232351 - 22 = 5304014232347 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5304014232353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 797113330 + ... + 797119983.

It is an arithmetic number, because the mean of its divisors is an integer number (884799489270).

Almost surely, 25304014232351 is an apocalyptic number.

5304014232351 is a deficient number, since it is larger than the sum of its proper divisors (1774381681809).

5304014232351 is a wasteful number, since it uses less digits than its factorization.

5304014232351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1594234425.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 5304014232351 its reverse (1532324104035), we get a palindrome (6836338336386).

The spelling of 5304014232351 in words is "five trillion, three hundred four billion, fourteen million, two hundred thirty-two thousand, three hundred fifty-one".

Divisors: 1 3 1109 3327 1594233313 4782699939 1768004744117 5304014232351