Base | Representation |
---|---|
bin | 100110100101110111111… |
… | …1011100110100011111101 |
3 | 200210001120221000102101011 |
4 | 1031023233323212203331 |
5 | 1143400110321203313 |
6 | 15140344133315221 |
7 | 1055126302546126 |
oct | 115135773464375 |
9 | 20701527012334 |
10 | 5304015022333 |
11 | 1765469228535 |
12 | 717b53a95b11 |
13 | 2c6221974121 |
14 | 144a03c2d04d |
15 | 92e8262193d |
hex | 4d2efee68fd |
5304015022333 has 4 divisors (see below), whose sum is σ = 5308227902880. Its totient is φ = 5299802141788.
The previous prime is 5304015022309. The next prime is 5304015022351. The reversal of 5304015022333 is 3332205104035.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5304015022333 - 221 = 5304012925181 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5304015022295 and 5304015022304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5304015022363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2106438385 + ... + 2106440902.
It is an arithmetic number, because the mean of its divisors is an integer number (1327056975720).
Almost surely, 25304015022333 is an apocalyptic number.
It is an amenable number.
5304015022333 is a deficient number, since it is larger than the sum of its proper divisors (4212880547).
5304015022333 is a wasteful number, since it uses less digits than its factorization.
5304015022333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4212880546.
The product of its (nonzero) digits is 32400, while the sum is 31.
The spelling of 5304015022333 in words is "five trillion, three hundred four billion, fifteen million, twenty-two thousand, three hundred thirty-three".
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