Base | Representation |
---|---|
bin | 1111011011111100110… |
… | …11110100111000110101 |
3 | 1212201001122022112212012 |
4 | 13231332123310320311 |
5 | 32142230430414031 |
6 | 1043355143534005 |
7 | 53214601215311 |
oct | 7557633647065 |
9 | 1781048275765 |
10 | 530402201141 |
11 | 194a4024016a |
12 | 8696675a305 |
13 | 3b02a9452c7 |
14 | 1b958c46b41 |
15 | dbe4c07b2b |
hex | 7b7e6f4e35 |
530402201141 has 8 divisors (see below), whose sum is σ = 553832424000. Its totient is φ = 507002749792.
The previous prime is 530402201107. The next prime is 530402201159. The reversal of 530402201141 is 141102204035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530402201141 - 210 = 530402200117 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530402201101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7657640 + ... + 7726593.
It is an arithmetic number, because the mean of its divisors is an integer number (69229053000).
Almost surely, 2530402201141 is an apocalyptic number.
It is an amenable number.
530402201141 is a deficient number, since it is larger than the sum of its proper divisors (23430222859).
530402201141 is a wasteful number, since it uses less digits than its factorization.
530402201141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15385755.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 530402201141 its reverse (141102204035), we get a palindrome (671504405176).
The spelling of 530402201141 in words is "five hundred thirty billion, four hundred two million, two hundred one thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.118 sec. • engine limits •