53040347331 has 4 divisors (see below), whose sum is σ = 70720463112. Its totient is φ = 35360231552.

The previous prime is 53040347329. The next prime is 53040347407. The reversal of 53040347331 is 13374304035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53040347331 - 2¹ = 53040347329 is a prime.

It is a super-2 number, since 2×53040347331² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53040347292 and 53040347301.

It is not an unprimeable number, because it can be changed into a prime (53040347831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8840057886 + ... + 8840057891.

It is an arithmetic number, because the mean of its divisors is an integer number (17680115778).

Almost surely, 2^53040347331 is an apocalyptic number.

53040347331 is a deficient number, since it is larger than the sum of its proper divisors (17680115781).

53040347331 is a wasteful number, since it uses less digits than its factorization.

53040347331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17680115780.

The product of its (nonzero) digits is 45360, while the sum is 33.

The spelling of 53040347331 in words is "fifty-three billion, forty million, three hundred forty-seven thousand, three hundred thirty-one".