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53040347407 is a prime number
BaseRepresentation
bin110001011001011100…
…110111100100001111
312001220110202211012101
4301121130313210033
51332111312104112
640211050415531
73555250341235
oct613134674417
9161813684171
1053040347407
1120548991063
12a3431315a7
13500390cc68
1427d243a955
1515a6758757
hexc5973790f

53040347407 has 2 divisors, whose sum is σ = 53040347408. Its totient is φ = 53040347406.

The previous prime is 53040347329. The next prime is 53040347417. The reversal of 53040347407 is 70474304035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53040347407 - 211 = 53040345359 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53040347417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26520173703 + 26520173704.

It is an arithmetic number, because the mean of its divisors is an integer number (26520173704).

Almost surely, 253040347407 is an apocalyptic number.

53040347407 is a deficient number, since it is larger than the sum of its proper divisors (1).

53040347407 is an equidigital number, since it uses as much as digits as its factorization.

53040347407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141120, while the sum is 37.

The spelling of 53040347407 in words is "fifty-three billion, forty million, three hundred forty-seven thousand, four hundred seven".