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5304044401 = 25121131651
BaseRepresentation
bin1001111000010010…
…10100101101110001
3111200122111101001221
410330021110231301
541330313410101
62234152025041
7245303430205
oct47411245561
914618441057
105304044401
112281aa4077
121040392181
13666b44516
14384608b05
152109b3aa1
hex13c254b71

5304044401 has 4 divisors (see below), whose sum is σ = 5325176304. Its totient is φ = 5282912500.

The previous prime is 5304044381. The next prime is 5304044411. The reversal of 5304044401 is 1044404035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5304044401 - 231 = 3156560753 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5304044411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10565575 + ... + 10566076.

It is an arithmetic number, because the mean of its divisors is an integer number (1331294076).

Almost surely, 25304044401 is an apocalyptic number.

It is an amenable number.

5304044401 is a deficient number, since it is larger than the sum of its proper divisors (21131903).

5304044401 is a wasteful number, since it uses less digits than its factorization.

5304044401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21131902.

The product of its (nonzero) digits is 3840, while the sum is 25.

The square root of 5304044401 is about 72828.8706558052. The cubic root of 5304044401 is about 1743.9567770172.

Adding to 5304044401 its reverse (1044404035), we get a palindrome (6348448436).

The spelling of 5304044401 in words is "five billion, three hundred four million, forty-four thousand, four hundred one".

Divisors: 1 251 21131651 5304044401