530412168373 has 4 divisors (see below), whose sum is σ = 531642823488. Its totient is φ = 529181513260.

The previous prime is 530412168367. The next prime is 530412168397. The reversal of 530412168373 is 373861214035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 373861214035 = 5 ⋅74772242807.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-530412168373 is a prime.

It is a super-3 number, since 3×530412168373³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530412168323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615326911 + ... + 615327772.

It is an arithmetic number, because the mean of its divisors is an integer number (132910705872).

Almost surely, 2^530412168373 is an apocalyptic number.

It is an amenable number.

530412168373 is a deficient number, since it is larger than the sum of its proper divisors (1230655115).

530412168373 is a wasteful number, since it uses less digits than its factorization.

530412168373 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1230655114.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 530412168373 in words is "five hundred thirty billion, four hundred twelve million, one hundred sixty-eight thousand, three hundred seventy-three".